Can you prove that #1^2+2^2+3^2+..+n^2=1/6n(n+1)(2n+1)#?
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- 1 2 1 x(lnx)2 dxconverges or diverges: Z 1 2 1 x(lnx)2 dx= lim b!1 Z b 2 1 x(lnx)2 dx= lim b!1 1 lnx b = lim b!1 1 lnb + 1 ln2 = 1 ln2: Since the integral Z 1 2 1 x(lnx)2 dxconverges, we conclude from the integral test that the series X1 n=2 1 n(lnn)2 converges. 5) Use the alternating series test to show that the following series converge.
2 Answers
Explanation:
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Explanation:
Let, #S_n=1^2+2^2+3^2+..+n^2, &, , f(n)=n^3, n in NNuu{0}.#
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